### Table 7. The stationary probability.

2000

Cited by 3

### Table 2. Stationary FAM

2000

### Table I: Summary Statistics for Parameter Posteriors Stationary Stationary

1998

Cited by 7

### Table I: Summary Statistics for Parameter Posteriors, Continued Stationary Stationary

1998

Cited by 7

### Table 1: Word Error Rates for stationary and non- stationary noise

### Table VI: Stationary states for HCN

1999

Cited by 1

### Table 1. Optimal policies for ve stationary cases

2005

"... In PAGE 3: ... By solving the MDP problem in (1) for each station- ary case, we obtain ve stationary optimal policies ci; i = 1; 2; ; 5 (which corresponds to Windows Explorer, Inter- net Explorer, Microsoft Outlook, Adobe Photoshop and Win- dows Media Player, respectively). Table1 illustrates the ve stationary optimal policies designed under limits bw = 0:2s and bl = 0:02. Each entry in Table 1 speci es probabilities for choosing actions GO ACTIV E and GO IDLE at a par- ticular system-state.... In PAGE 3: ... Table 1 illustrates the ve stationary optimal policies designed under limits bw = 0:2s and bl = 0:02. Each entry in Table1 speci es probabilities for choosing actions GO ACTIV E and GO IDLE at a par- ticular system-state. For instance, under the second station- ary case corresponding to application Internet Explorer (c2), when the bu er is empty and the HDD is idle, (i.... In PAGE 3: ....e., when there is no service request in the system, because all ve policies agree on GO ACTIV E action for other states. The second column from right in Table1 gives the power con-... In PAGE 5: ... Each en- try in Table 2 gives the mode, system-state and the prob- abilities for choosing policies c2 and c5 for that mode and system-state pair. For instance, when Internet Explorer ac- cesses the hard disk (that is, mode 2) and the disk bu er be- comes empty (that is, the system-state (0; 1) which is the rst bold entry in the 2 row in Table 2), the power man- ager applies the policy c5 (instead of the mode-matching c2) which puts the disk to idle with a probability of 0:57 ac- cording to Table1 . The optimal switching rule consumes a power of 1:46W.... ..."

Cited by 8

### Table 1: Stationary points for Example 1

1995

"... In PAGE 12: ... The objective function is plotted in Figure 3 and reveals a nonconvex curve with multiple stationary and in ection points. In fact, there are two local minima, one of which is the global one, a local maximum and several in ection points, and the values of y1 where these occur (excluding the maxima at the boundaries of the feasible region) are given in Table1 . A local solver will converge at best to a local minimum, with no guarantee of obtaining the global solution.... In PAGE 20: ... This will not be the case in general, where the global solution of the stability problem may be the only stationary point with a negative distance.If the postulated solution is the global LL solution, which is also given in Table1 0, then the tangent plane distance function will be nonnegative everywhere, and this is shown in Figure 5. Again it is a nonconvex curve, and the branch and bound algorithm correctly identi es the global solution in 62 iterations, with the GOP algorithm consuming a total time of 0.... In PAGE 20: ...35 cpu sec. The global solutions of the stability problem for both these cases are given in Table1 0, along with the usual computational results. The iteration at which the tangent plane distance function becomes negative occurs very early, re ecting behavior already seen in the case of the NRTL equation.... In PAGE 33: ...30 62 38 i = 2 L1 = :478 0:04358 0:99911 ?0:00088 0.04358 ({) ({) ({) Table1 0: Global solutions for Example 4... In PAGE 34: ... ij = exp (? uij=RT) with T in K Components ij i j uij=R uji=R C2H6O2 { C12H26O 1 2 247:20 69:69 C2H6O2 { CH3NO2 1 3 54:701 467:88 C12H26O { CH3NO2 2 3 305:52 133:19 Table1 1: Binary data for Example 5 C2H6O2 (1) { C12H26O (2) { CH3NO2 (3) Parameter i = 1 i = 2 i = 3 qi = q0 i 2:2480 7:3720 1:8680 ri 2.4088 8.... In PAGE 34: ...8495 2.0086 li ?0:6048 ?0:4620 ?0:3056 Table1 2: Pure component data for Example 5... In PAGE 35: ...30321 ?0:02161 0.22910 Table1 3: Data and solutions for Example 5, Conditions (i) Solutions for Ethylene Glycol (1) { Lauryl Alcohol (2) { Nitromethane (3) at T = 295K, P = 1 atm zL1 i zL2 i 0 i (z) y i F cpu NI NF Comp. Solution (|) (|) (|) (|) (|) (sec) (|) (%) i = 1 Trivial L 0:2 (|) ?0:50936 0:01254 ?0:22827 7.... In PAGE 35: ...96788 ?0:02272 0.28124 Table1 4: Solutions for Example 5, Conditions (ii)... In PAGE 36: ... ij = exp (? uij=RT) with T in K , R = 1:9872 Components ij i j uij uji C3H8O { C4H10O 1 2 ?193:140 415:850 C3H8O { H2O 1 3 424:025 103:810 C4H10O { H2O 2 3 315:312 3922:500 Table1 5: Binary data for Example 6 SBA (1) { DSBE (2) { Water (3) Parameter i = 1 i = 2 i = 3 qi 3.6640 5.... In PAGE 36: ...0909 0.9200 Table1 6: Pure component data for Example 6 SBA (1) { DSBE (2) { Water (3) Tray Temperature Pressure (|) (K) (atm) 28 363.20 1.... In PAGE 36: ...50 1.140 Table1 7: Temperatures and Pressures for Example 6... In PAGE 37: ...57214 ?0:40139 .43088 Table1 8: Data and solutions for Example 6, Conditions (i) on Tray 28... In PAGE 38: ...58282 ?0:38291 .98044 Table1 9: Data and solutions for Example 6, Conditions (ii) on Tray 28... ..."

Cited by 18

### Table 1. Roots (stationary points) found and performance

"... In PAGE 4: ...eeds of z1 = 0.0185 and z1 = 0.5 were considered. Results are presented in Table1 , which shows the roots (stationary points) found, and the value of the tangent plane distance D at each root. Both feeds are unstable, as indicated by the negative values found for D.... In PAGE 4: ...inds all the stationary points, including the global minimum at x1 = 0.0751. Note also that the presence of multiple real volume roots does not present any difficulty, since the solver simply finds all roots for the given system. Also included in Table1 are the number of 0.05 0.... In PAGE 4: ...eeds of z1 = 0.1, 0.4, and 0.6 were considered, with results shown in Table1 . The first feed is stable and the others unstable, which is consistent with known phase behavior (Prausnitz, et.... ..."

### Table 2: Complexity of the Di erential Stationary qd

1998

"... In PAGE 10: ...Table2 . We have not included the e ort necessary to compute qi and ei since it has to be done only once.... ..."

Cited by 3