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35
Multicasting in the Hypercube, Chord and Binomial Graphs
, 2009
"... We discuss multicasting for the n-cube network and its close variants, the Chord and the Binomial Graph (BNG) Network. We present simple transformations and proofs that establish that the sp-multicast (shortest path) and Steiner tree problems for the n-cube, Chord and the BNG network are NP-Complete ..."
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We discuss multicasting for the n-cube network and its close variants, the Chord and the Binomial Graph (BNG) Network. We present simple transformations and proofs that establish that the sp-multicast (shortest path) and Steiner tree problems for the n-cube, Chord and the BNG network are NP
[NP3546/20A]
"... Note: before using this routine, please read the Users ’ Note for your implementation to check the interpretation of bold italicised terms and other implementation-dependent details. 1 Purpose G05MJF generates a vector of pseudo-random integers from the discrete binomial distribution with parameters ..."
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Note: before using this routine, please read the Users ’ Note for your implementation to check the interpretation of bold italicised terms and other implementation-dependent details. 1 Purpose G05MJF generates a vector of pseudo-random integers from the discrete binomial distribution
[NP3546/20A]
"... Note: before using this routine, please read the Users ’ Note for your implementation to check the interpretation of bold italicised terms and other implementation-dependent details. 1 Purpose G05MCF generates a vector of pseudo-random integers from the discrete negative binomial distribution with p ..."
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Note: before using this routine, please read the Users ’ Note for your implementation to check the interpretation of bold italicised terms and other implementation-dependent details. 1 Purpose G05MCF generates a vector of pseudo-random integers from the discrete negative binomial distribution
[NP3666/22]
"... Note: before using this routine, please read the Users ’ Note for your implementation to check the interpretation of bold italicised terms and other implementation-dependent details. 1 Purpose G05MCF generates a vector of pseudorandom integers from the discrete negative binomial distribution with pa ..."
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Note: before using this routine, please read the Users ’ Note for your implementation to check the interpretation of bold italicised terms and other implementation-dependent details. 1 Purpose G05MCF generates a vector of pseudorandom integers from the discrete negative binomial distribution
The All-Ones Problem for Binomial Trees, Butterfly and Benes Networks
"... The all-ones problem is an NP-complete problem introduced by Sutner [11], with wide applica-tions in linear cellular automata. In this paper, we solve the all-ones problem for some of the widely studied architectures like binomial trees, butterfly, and benes networks. ..."
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The all-ones problem is an NP-complete problem introduced by Sutner [11], with wide applica-tions in linear cellular automata. In this paper, we solve the all-ones problem for some of the widely studied architectures like binomial trees, butterfly, and benes networks.
SOME COMBINATORICS OF BINOMIAL COEFFICIENTS AND THE BLOCH-GIESEKER PROPERTY FOR SOME HOMOGENEOUS BUNDLES
, 2001
"... Abstract. A vector bundle has the Bloch-Gieseker property if all its Chern classes are numerically positive. In this paper we show that the non-ample bun-dle pPn (p+ 1) has the Bloch-Gieseker property, except for two cases, in which the top Chern classes are trivial and the other Chern classes are p ..."
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are positive. Our method is to reduce the problem to showing, e.g. the positivity of the coe-cient of tk in the rational function (1+t) (np)(1+3t)( n
The Effects of an Arcsin Square Root Transform on a Binomial Distributed Quantity
"... This document provides proofs of the following: • The binomial distribution can be approximated with a Gaussian distribution at large values of N. • The arcsin square-root transform is the variance stabilising transform for the binomial distribution. • The Gaussian approximation for the binomial dis ..."
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and Poisson distributions. 1 Gaussian Approximation to the Binomial Distribution The binomial distribution P (n|N) = N! n!(N − n)!p nq(N−n) (1) gives the probability of obtaining n successes out of N Bernoulli trials, where p is the probability of success and q = 1 − p is the probability of failure
Abstract Multicast Session Membership Size Estimation
, 1998
"... The problem of estimating the number of members in a multicast session through probabilistic polling corresponds to that of estimating the parameter n of the Binomial np, distribution. This allows an interval estimator for n to be derived. The tradeoff between the relative dispersion of this estimat ..."
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The problem of estimating the number of members in a multicast session through probabilistic polling corresponds to that of estimating the parameter n of the Binomial np, distribution. This allows an interval estimator for n to be derived. The tradeoff between the relative dispersion
An extension of Lucas’ theorem
- Proc. Amer. Math. Soc
"... Abstract. Let p be a prime. A famous theorem of Lucas states that ( mp+s) ≡ ( np+t m) ( s) (mod p) ifm, n, s, t are nonnegative integers with s, t < p. Inthispaper n t we aim to prove a similar result for generalized binomial coefficients defined in terms of second order recurrent sequences with ..."
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Cited by 26 (16 self)
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Abstract. Let p be a prime. A famous theorem of Lucas states that ( mp+s) ≡ ( np+t m) ( s) (mod p) ifm, n, s, t are nonnegative integers with s, t < p. Inthispaper n t we aim to prove a similar result for generalized binomial coefficients defined in terms of second order recurrent sequences
18.443 Statistics for Applications
"... First, here is some notation for binomial probabilities. Let X be the number of successes in n independent trials with probability p of success on each trial. Let q ≡ 1−p. Then we know that EX = np, the variance of X is npq where q = 1 − p, and so the ..."
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First, here is some notation for binomial probabilities. Let X be the number of successes in n independent trials with probability p of success on each trial. Let q ≡ 1−p. Then we know that EX = np, the variance of X is npq where q = 1 − p, and so the
Results 1 - 10
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35