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Products of orthogonal projections and polar decompositions
- Linear Algebra Appl
"... Abstract We characterize the sets X of all products P Q, and Y of all products P QP , where P, Q run over all orthogonal projections and we solve the problems arg min{ P − Q : (P, Q) ∈ Z}, for Z = X or Y. We also determine the polar decompositions and Moore-Penrose pseudoinverses of elements of X. ..."
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Abstract We characterize the sets X of all products P Q, and Y of all products P QP , where P, Q run over all orthogonal projections and we solve the problems arg min{ P − Q : (P, Q) ∈ Z}, for Z = X or Y. We also determine the polar decompositions and Moore-Penrose pseudoinverses of elements of X.
© Hindawi Publishing Corp. ON MIXED-TYPE REVERSE-ORDER LAWS FOR THE MOORE-PENROSE INVERSE OF A MATRIX PRODUCT
, 2003
"... Some mixed-type reverse-order laws for the Moore-Penrose inverse of a matrix product are established. Necessary and sufficient conditions for these laws to hold are found by the matrix rank method. Some applications and extensions of these reverse-order laws to the weighted Moore-Penrose inverse are ..."
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Some mixed-type reverse-order laws for the Moore-Penrose inverse of a matrix product are established. Necessary and sufficient conditions for these laws to hold are found by the matrix rank method. Some applications and extensions of these reverse-order laws to the weighted Moore-Penrose inverse are also given. 2000 Mathematics Subject Classification: 15A03, 15A09. If A and B are a pair of invertible matrices of the same size, then the product AB is nonsingular, too, and the inverse of the product AB satisfies the reverse-order law (AB)−1 = B−1A−1. This law can be used to find the properties of (AB)−1, as well as to simplify various matrix expressions that involve the inverse of a matrix product. However, this formula cannot trivially be extended to the Moore-Penrose inverse of matrix products. For a general m×n complex matrix A, the Moore-Penrose inverse A† of A is the unique n×m matrix X that satisfies the following four Penrose equations: (i) AXA=A,