### Table 2: Space requirement of our FM-KZ index with parameter k, for different values of k.

"... In PAGE 14: ... We omit the spaces used by the Huffman table, the constant-size tables for rank, and array C, as they are all negligible. A similar study is carried out on Kautz-Zeckendorf coding in Table2 , although in this case there is no array Bh. The space is not the result of a tension between B and Bh, but between the length of the header and the number of different codewords of each length.... ..."

### Table 3. Effect of varying the document length correction parameter kz

1994

Cited by 209

### Table 4. cluster size LLR K(z) pop

"... In PAGE 8: ... Arbitrary precision arithmetic was necessary for the computation of the very low p-values. The corresponding clusters are described in Table4 , displaying LLR value, compactness, size, population, number of cases, incidence rate and approximated computed p-value. Figure 5 shows the selected clusters a, c , f, g, o and r within the Pareto-set.... ..."

### TABLE 3 Products of Ion Implantation of Kz+ , Na+ and S+ into Water Ice

### Table 2: Fractal and Sensitivity Analysis Results. M Bx By Bz Kx Ky Kz SPEED

1993

Cited by 1

### Table 4. 2D and 3D Virtual Screening of SARS-CoV Protease Using KZ7088 Pharmacophore Points

2004

"... In PAGE 3: ... Most of the hit compounds retrieved are drug-like and satisfied the rules describe above. Table4 contains the data obtained from the virtual screening. The number of compounds screened was over 3.... In PAGE 4: ... The model permits the retrieval of compounds having five out of the six hydrogen bonds. The results are displayed in Table4 and correspond to the columns under 3D search without volume constrains. The total number of the unique 3D hits is 7083.... ..."

Cited by 1

### Table 6.12 Percentage weight of the hybrid model tuning parameter Kz0 of the initial moisture ratio at the beginning of the drying section (z0).

2004

### Table 2: Computation of relations in invariants and equivariants for D3 + D3 with and without use of Hilbert series and as in Algorithm 3.3. by the t-invariant in K[z] of degree 1. Since has no trivial irreducible representation there exists no t-invariant of degree 1 and thus J \ HU 1 (K[z; y]) is empty. Because of the symmetry this is equivalent to J \ HU 1 (K[z; y; u]) = J \ HU 1 (K[y; u]).

"... In PAGE 16: ...f0 = [wr2 ? wi2; ?2 wr wi; 0; 0]; f1 = [vr wr ? vi wi; ?vr wi ? vi wr; 0; 0]; f2 = [vr2 ? vi2; ?2 vr vi; 0; 0]; h0 = [0; 0; wr2 ? wi2; ?2 wr wi]; h1 = [0; 0; vr wr ? vi wi; ?vr wi ? vi wr]; h2 = [0; 0; vr2 ? vi2; ?2 vr vi] Table2 shows some statistics of the computations of the relations. With the algorithms in subsection 3.... ..."