### Table 3. Fundamental Scale used in Pairwise Comparison

"... In PAGE 9: ...able 2. Final SFM Grade Making Process (LEI) ...............................................................................29 Table3 .... In PAGE 60: ... Elements can be compared if they have the uniform scale. To perform assessment using Fuzzy AHP we should fuzzified the original Pairwise Comparison Ma- trice (Table 10 ) using the conversion numbers in Table3 , then the result is as shown in Table 11. Table 10.... ..."

### Table 1. A fundamental 1 to 9 scale

### Table 4 :pixel distance between reference Fundamental matrix and estimated Fundamental matrix (LMEDS)

"... In PAGE 5: ...08 Table 2 :duration of matching process (s.) Scene quot;Zhang quot; method Proposed Iterative method Proposed Vector method 1 119 44 25 2 120 39 25 Table 3 :Number of matches found Table4 and 5 give the computed distance between the reference Fundamental matrix, and the estimated one, computed with the LMEDS and RANSAC algorithms. ... ..."

### Table 1: Fundamental Frequency Ratios in the Scales of Just Intonation and Equal Temperament.

1998

"... In PAGE 6: ... The western ear has become accustomed to equal temperament, and the tuning differences are hardly noticeable. The intervals in the just scale are presented in Table1 , along with their numerical ratios. For each interval in the just scale, the closest numerical ratio and corresponding interval in the scale of equal temperament are also presented.... In PAGE 7: ... Method 2 Find two harmonics, hQ i and hR j , one from each note, which occur at the same frequency hQ i = hR j . Then the ratio i : j can be used with Table1 to approximate the just intonation interval of the note pair. Notes.... In PAGE 8: ... or a quarter of the way from hQ 1 to hQ 2 . Combined with Table1 , this is sufficient information to deduce that Q arrownortheast R is a major third. Fig.... In PAGE 8: ...ig. 3 shows the use of Method 2. In this case, the first 6 harmonics of Q are detectable, as are the first 5 harmonics of R. The 5th harmonic of Q occurs at the same location on the frequency axis as the 4th harmonic of R, and, combined with Table1 , this is sufficient information to deduce that Q arrownortheast R is a major third. Compounding Intervals These proposed methods are not specifically designed to handle the case where the frequency of the first harmonic of R is greater than the frequency of the octave above Q, i.... In PAGE 8: ... The frequency ratio will still be valid for larger intervals, but the naming of these intervals is not handled by Method 1. The modification is to name the interval as a number of octaves plus an interval from Table1 . If the ratio can be written or approximated in the form 2k+12n 12 then the interval is n octaves, plus the interval in Table 1 corresponding to the ratio 2 k... In PAGE 8: ... The modification is to name the interval as a number of octaves plus an interval from Table 1. If the ratio can be written or approximated in the form 2k+12n 12 then the interval is n octaves, plus the interval in Table1 corresponding to the ratio 2 k... In PAGE 9: ... This augmentation also allows Method 1 to detect intervals less than an octave. If h1(R) falls below h1(Q), Method 1 is still valid and the interval can be considered to be an octave less than the interval found in Table1 . For example, If h1(R) = 0.... In PAGE 9: ... Since an increase of an octave corresponds to about a doubling of f0, doubling each frequency ratio in the table corresponds to increasing each frequency ratio by an octave: if 5:4 corresponds to a major third, then 10:4 corresponds to an octave plus a major third. Method 2 can then identify intervals larger than the octave by finding coincident harmonics and comparing the ordinals to those in Table1 , as well as whole number multiples of the intervals in Table 1. It is impossible to check every whole number multiple of every interval, so a limit should be imposed to make the method computationally tractable.... In PAGE 9: ... Since an increase of an octave corresponds to about a doubling of f0, doubling each frequency ratio in the table corresponds to increasing each frequency ratio by an octave: if 5:4 corresponds to a major third, then 10:4 corresponds to an octave plus a major third. Method 2 can then identify intervals larger than the octave by finding coincident harmonics and comparing the ordinals to those in Table 1, as well as whole number multiples of the intervals in Table1 . It is impossible to check every whole number multiple of every interval, so a limit should be imposed to make the method computationally tractable.... ..."

Cited by 4

### Table 1: Estimated fundamental matrices.

1998

"... In PAGE 5: ...he maximum square distance error: 0.122 pixeln29. The enhanced linear estimation results in the slightly din0berent estimates for the matrix representations of Eqs. n286n29, 8n29, and n289n29 presented in Table1 . Because of a n0cnite range of exhausting the parameters n0b; n0c the minimum total error for both the representations in Eq.... In PAGE 6: ...145 pixeln29. Stereo pairs with the overlaid epipolar lines corresponding to Table1 are shown in Figures 1-3. Here, all the three cases give practically the same precision of the resulting epipolar lines.... ..."

### TABLE I STATISTICS ON THE SHORT-DISTANCE CONNECTION

2000

Cited by 144

### Table 1 Synaptic parameters that scale the short-term dynamics

"... In PAGE 2: ...) The parameters U, D, and F were chosen in our computer model from Gaussian distributions that reflect data reported in Markram and others (1998) and Gupta and others (2000) for each type of connection (note that the parameter U is according to Markram and others [1998] largely determined by the initial release probability of the synaptic re- lease sites involved). Depending on whether the input was excitatory (E) or inhibitory (I), the mean values of these 3 parameters U, D, F (with D, F expressed in seconds) were chosen to have the mean values that were reported in these articles (see Table1 ). The standard deviation (SD) of each parameter was chosen to be 50% of its mean (with negative values replaced by values chosen from an uniform distribution between zero and two times the mean).... In PAGE 2: ... Each layer consisted of a population of excitatory neurons and a population of inhibitory neurons with a ratio of 4:1. Synaptic connections between the neurons in any pair of the resulting 6 populations were randomly generated in accordance with the empirical data from Table1 and Figure 1. Most circuits that were simulated consisted of 560 neurons.... In PAGE 9: ... The degree distributions of neurons for all 5 types of circuits are shown in Figure 7. An important structural feature of all circuit types considered until now is the alignment of synapse type with regard to pre- and postsynaptic neuron type according to Table1 . In order to analyze the impact of the alignment of dynamic synapses on the performance, we randomly exchanged the synaptic parameter triplets, that is, U, D, and F, that define the short-term plasticity between all synapses.... ..."

### Table 1 Synaptic parameters that scale the short-term dynamics

2007

"... In PAGE 2: ... The parameters U, D, and F were chosen in our computer model from Gaussian distributions that reflect data reported in Markram and others (1998) and Gupta and others (2000) for each type of connection (note that the parameter U is according to Markram and others [1998] largely determined by the initial release probability of the synaptic re- lease sites involved). Depending on whether the input was excitatory (E) or inhibitory (I), the mean values of these 3 parameters U, D, F (with D, F expressed in seconds) were chosen to have the mean values that were reported in these articles (see Table1 ). The standard deviation (SD) of each parameter was chosen to be 50% of its mean (with negative values replaced by values chosen from an uniform distribution between zero and two times the mean).... In PAGE 2: ... Each layer consisted of a population of excitatory neurons and a population of inhibitory neurons with a ratio of 4:1. Synaptic connections between the neurons in any pair of the resulting 6 populations were randomly generated in accordance with the empirical data from Table1 and Figure 1. Most circuits that were simulated consisted of 560 neurons.... In PAGE 9: ... The degree distributions of neurons for all 5 types of circuits are shown in Figure 7. An important structural feature of all circuit types considered until now is the alignment of synapse type with regard to pre- and postsynaptic neuron type according to Table1 . In order to analyze the impact of the alignment of dynamic synapses on the performance, we randomly exchanged the synaptic parameter triplets, that is, U, D, and F, that define the short-term plasticity between all synapses.... ..."

### Table 2n3a Distances between the fundamental matrices estimated by din1berent techniques

1996

"... In PAGE 41: ...oints. In our experimentn2c we set N n3d 50000. Using this methodn2c we can compute the distance between each pair of fundamental matricesn2c and we obtain a symmetric matrix. The result is shown in Table2 n2c where only the upper triangle is displayed n28because of symmetryn29. We arrive at the following conclusionsn3a n0f The linear method is very bad.... ..."

### Table 1. Residual error of the fundamental matrix estimative (quadratic distance in square pixel fractions).

"... In PAGE 7: ... The sets are used with each algorithm where they apply to calculate an estimative of the fundamental matrix. Table1 shows the residual error for these estimative for each set-algorithm combination. To test the efficiency of the algorithms we generated a set of 20 points, and the resulting residual error for each estimative of the fundamental matrix is shown in Tab.... In PAGE 7: ... As in the previous case, the sets are used with each algorithm where they apply to calculate an estimative of the fundamental matrix. Table1 shows the residual error for these estimative for each set-algorithm combination. Again, the efficiency of the algorithms was tested against another set of 20 points, and the resulting residual error for each estimative of the fundamental matrix is shown in Tab.... ..."