| X. Wan, Y. Wang, and W. Chen, "Dynamic range analysis for the implementation of fast transform," IEEE Trans. Circiuts Syst. Vid. Technol., vol. 5, pp. 178--180, Apr. 1995. |
....not employed in [40] C. Dynamic Range Analysis The elimination of the floating point and fixed point multiplications enables the binDCT to be implemented with narrower data bus than other fast algorithms. The dynamic range of the binDCT is analyzed in this section using the method as shown in [47]. Assume the original input data are eight bit signed integers, ranging from to 127, as processed in the JPEG standard [3] To check the dynamic range of the binDCT, we examine the signs of the binDCT coefficients and find out the set of input data that would generate the maximum or minimum ....
X. Wan, Y. Wang, and W. Chen, "Dynamic range analysis for the implementation of fast transform," IEEE Trans. Circiuts Syst. Vid. Technol., vol. 5, pp. 178--180, Apr. 1995.
....advantage of in [40] C. Dynamic Range Analysis The elimination of the oating point and xed point multiplications enables the binDCT to be implemented with narrower data bus than other fast algorithms. The dynamic range of the binDCT is analyzed in this section using the method as shown in [47]. Assume the original input data are 8 bit signed integers, ranging from 128 to 127, as processed in the JPEG standard [3] To check the dynamic range of the binDCT, we examine the signs of the binDCT coecients and nd out the set of input data which would generate the maximum or minimum outputs ....
X. Wan, Y. Wang, and W. Chen, \Dynamic range analysis for the implementation of fast transform," IEEE Trans. Cir. and Syss. for Vid. Tech., vol. 5 (2), pp. 178-180, Apr. 1995.
....to decide the necessary exponent bit width for our IDCT, we collected the histogram information of exponents for all the variables in the IDCT algorithm during a video sequence decoding (see Fig. 7) The range of these exponents lies in [ 22, 10] which is consistent with the theoretical result in [7]. From the dynamic range analysis above, we know that a 5 bit exponent can almost cover such a range except when numbers are extremely small, while a 6 bit exponent can cover the entire range. However, our experiment shows that 5 bit exponent is able to produce the same PSNR as an 8 bit exponent. ....
X. Wan, Y. Wang, W H. Chen, "Dynamic range analysis for the implementation of fast transform," IEEE Trans. Circuits. Syst. for Video Technology, vol. 5, Apr. 1995, pp.178-180
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